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2 years ago

EFECTUAR POR FAVORRRRRRRRRRRRRRRRRRRRRRRRRRRR

Mathematics

1 answer:

Hatshy [7]2 years ago

4 0

Answer:

180

Step-by-step explanation:

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The first term of a sequence is a multiple of 3 The second term of this sequence is 6 less than the first term. The third term i

Mekhanik [1.2K]

Answer:

First term $= 15$

Second term $= 9$

Third term $= 3$

Step-by-step explanation:

Given,

First term $= 3x$

Second term $= 3x - 6$

Third term $= \frac{1}{5} (3x) = \frac{3x}{5}$

Also,

$3x - \frac{3x}{5} = 12$

$\frac{15x}{5} - \frac{3x}{5} = 12$

$\frac{15x - 3x}{5} = 12$

$15x - 3x = 12 \times 5$

$12x = 60$

$x = \frac{60}{12}$

$x = 5$

With the value of $x$ , we conclude that the first three terms are as follows:

First term $= 3x = 3×5 = 15$

Second term $= 3x - 6 = 15 - 6 = 9$

Third term $= \frac{3x}{5} =\frac{15}{5}= 3$

7 0

2 years ago

Which expression is equivalent to this polynomial expression? (2x2-3y2)(4x4+6x2y2+9y4)

Lelechka [254]

Answer:

8x^6-27y^6

Step-by-step explanation:

simplify the expression

3 0

2 years ago

Find each absolute value | 4+2i | | 5-i | | -3i |

galina1969 [7]

How to get answer for number 1: | 4+2i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}$

How to get answer for number 2: | 5-i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}$

Number 3 how to get answer: | -3i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3$