The answer is C to this question
Answer:
It's purpose is to access a webpage.
Explanation:
A URL contains detailed information on the webpage such as, the domain name, protocol, and path. This information directs the browser to the desired page.
Answer:
import java.util.Scanner;
public class TestClock {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter two integer numbers");
int num1 = in.nextInt();
int num2 = in.nextInt();
int newSum=num1+10;
System.out.println("The first number is "+num1);
do{
System.out.println(newSum);
newSum +=10;
}while (newSum <=num2);
}
}
Explanation:
Using Java Programming language
- Prompt user for the two inputs and save them as num1 and num2(Using the scanner class)
- Create a new Variable newSum = num1+10
- Create a do...while loop to continually print the value of newSum, and increment it by 10 while it is less or equal to num2
The answer & explanation for this question is given in the attachment below.
Answer:
Check the explanation
Explanation:
For 9th byte , it is from 8*8 bit to 9"8th bit so each word consists of 64 bits , to find word address u have to divide 8*8 by 64.
Offset within word = 9*8modulo 64.
For 27th byte , word address = 8*27/64.
Offset within word = 27* 8 modulo 64
For 21th byte , word address = 8*31/64
Offset within the word = 31*8 modulo 64
For 120 , word address = 8*120/64
Offset within the word = 120*8 modulo 64.
