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kipiarov [429]
3 years ago
10

Match the values associated with this data set to their correct descriptions.

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0
The correct matches are as follows:

quartile

10.5

<span>median
41

third quartile
</span>38.5<span>

the difference of the largest value and the median
49-41 = 8

Hope this answers the question. Have a nice day. Feel free to ask more question.

</span>
Gennadij [26K]3 years ago
6 0

For PLATO Users

FIRST OF ALL MissPhiladelphia Is Clearly INCORRECT

If You Just Want The Answer, Check The Pictures Below

People Who Want To Learn I Explained Step By Step

Given:

6,7,15,36,41,43,47,49

<u>To Find The Median </u>

Use Process Of Elimination

36,41

Then Split Those Numbers Apart

36,37,38,39,40,41

Again Process Of Elimination

38,39

You cannot split these whole numbers

Therefor Your Answer Is

38.5

<u>To Find The Quartiles</u>

6,7,15,36,41,43,47,49

Median:38.5

Put The Given Into Pairs

\left[\begin{array}{ccc}6&7\\15&36\\41&43\\47&49\end{array}\right]

Notice There Are 4 EVEN Pairs.

Ever Heard Of The Quote " Read Between The Lines "

There Are Spaces Between Each Of The 4 Pairs

Those Spaces Represent One Quartile

<u>To Find The First Quartile </u>

The First Space Of The EVEN Pairs Is Between 7 and 15

Split Those Numbers

7,8,9,10,11,12,13,14,15

Process Of Elimination

11

<h3><em>The Second Space Of The EVEN Pairs Is Actually The Median </em></h3>

<u>To Find The Third Quartile</u>

The Third Space Of The EVEN Pairs Is Between 43 and 47

Split Those Numbers

43,44,45,46,47

Process Of Elimination

45

<u>To Find The Difference Of The Largest Value And Median</u>

6,7,15,36,41,43,47,49

Median:38.5

Q1:11

Q3:45

The Median We All Know Is 38.5

The Largest Value Is 49

Subtract The Numbers

\left[\begin{array}{ccc}49-38.5\end{array}\right]

10.5


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