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2 years ago

3. If you were to graph the equation y = -x + 1 and graph the equation y

Mathematics

1 answer:

Nat2105 [25]2 years ago

5 0

Answer: (3, -2)

Step-by-step explanation: graphed both of em on desmos and thats the intersection.

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Olivia borrows $50 from her mom to buy some art supplies. Olivia spends $32.15 on art supplies and gives the change back to her

frutty [35]

Mom's view is that she loses 50 dollars, but gains back 17.85 dollars as change from her daughter.

Olivia's view is that she gained 50 dollars from her mom, spent 32.15 dollars, then gave back the 17.85 change to her mom, so she didn't gain any money.

Mom's point of view: -$50 + $17.85 and Mom's point of view: -$50 + $17.85 are the correct answers, but technically, Olivia still owes her mom 32.15 dollars.

6 0

3 years ago

Please help me!! Solve for 'a'. <br> b=(4*a)-3<br> ----------<br> 4

lilavasa [31]

here u go! i hope this is correct :)

8 0

2 years ago

Read 2 more answers

The weight of meteorite A is 5 times the weight of meteorite B. If the sum of their weights is 132 tons, find the weight of each

sladkih [1.3K]

Answer:

A: 105.6 B: 26.40

Step-by-step explanation:

if you divide 132 by 5, you get Meteorite B, 26.40, then minus that from 132, and you get Meteorite A, 105.6.

To check, do 26.40x5 and you should get 132.

3 0

3 years ago

Find the area of a parallelogram whose base is 12cm and altitude is 8cm. Also find the other base of its corresponding altitude

lukranit [14]

Answer:

Step-by-step explanation:

Area of parallelogram = base * height

= 12 * 8

= 96 cm²

Area of parallelogram = 96

base * height = 96

base = 96/height

base = 96/16

base = 6 cm

6 0

2 years ago

Read 2 more answers

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago