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SpyIntel [72]
3 years ago
5

Help meeeeeeeeeeeeeeeee

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0
I think it's just determining what the negative means. Negative with the x axis means to the left (because the left side is negative). Negative with the y axis is down (because the down side is negative.) So once you know that, it's obviously D because both are negative.

I hope that helped!

- mathwizzard3
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What is the product of (2x-1)(x+4)
Novay_Z [31]

Answer:

\large\boxed{(2x-1)(x+4)=2x^2+7x-4}

Step-by-step explanation:

(2x-1)(x+4)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(2x)(x)+(2x)(4)+(-1)(x)+(-1)(4)\\\\=2x^2+8x-x-4\qquad\text{combine like terms}\\\\=2x^2+(8x-x)-4\\\\=2x^2+7x-4

4 0
3 years ago
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PolarNik [594]

1 = 1/4(2x+8)

1 = 1/2x + 2

1 - 2 = 1/2x

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x = (-1) : 1/2 = (-1) × 2/1 = (-2)

Answer : x = (-2)

3 0
3 years ago
Read 2 more answers
Order the following numbers from least to greatest. √11, -0.4, (-4/3), 0.8, √2
agasfer [191]

Answer:

(-4/3), 0.4, 0.8, √2, √11

Step-by-step explanation:

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0.4

(-4/3) = -1.33333333333333333333333333333333333333333333333333333333

0.8

√2=1.414213562373095048801688724209698078569671875376948073176


Thus :

(-4/3)

0.4

0.8

√2

√11

8 0
3 years ago
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Over [174]
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2 years ago
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Reika [66]

Answer:

\frac{-27b^{6}}{c^{18}}

Step-by-step explanation:

first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have -27b^{6}c^{-18}. Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18=\frac{1}{c^{18}}, plug it in and you get \frac{-27b^{6}}{c^{18}}

6 0
3 years ago
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