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pav-90 [236]
3 years ago
8

Solve for q(x) and r(x). (4x^3-3x^2+5x-7)/(x-2) = q(x)+ r(x)/(x-2)

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0
By synthetic division,

q(x) = 4x^2 +5x +15

r(x) = 23

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Write down the exact value of:<br> a) cos 60°<br> b) sin 0°<br> c) tan 45°
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Read 2 more answers
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

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And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
3 years ago
In the given table we note that there are six clear subintervals: [0, 0.5], [0.5, 1.0], [1.0, 1.5], [1.5, 2.0], [2.0, 2.5], and
gizmo_the_mogwai [7]

Answer:

The width is 0.5.

Δt, can be stated as follows = 0.5

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The change is 0.5

4 0
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