Answer:
1. Write the following as a mixed number.
2. Write as an improper fraction
3. Perform the operation and write the answer in simplest form.
a)4/7*3/11= 12/77
b)6/10 / 12/7= 7/20
c)5 1/7*3 1/9= 16
d)6 3/7 / 1 13/14= 10/3
Hope this helps
Step-by-step explanation:
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>
Required algebraic expression is 3/z
Hope this helps let me know if it does :)
