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vaieri [72.5K]
3 years ago
11

What is the solution to the system of equations? -2x + y = -5 3x – 2y = 12 A) (3, 1) B) (6, 3) C) (-2, -9) D) (-2, -1)

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

The correct answer is D) (-2, -1)

Step-by-step explanation:

In order to solve this system of equations, start by multiplying the entire first equation by 2. Then add the two equations together. This will get the y's to cancel and allow you to solve for x.

-4x + 2y = -10

3x - 2y = 12

---------------------

-x = 2

x = -2

Now that we have the value for x, we can find y by plugging the x value into either equation.

-2x + y = -5

-2(2) + y = -5

-4 + y = -5

y = -1

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The equation is:

I=100+12J+5T+7S+5H-8M

The given information is that I=197, J=5, T=5, H=3, and M=3, and we’re trying to solve for the amount of shorts (S) he sold.

We can plug in the variables into the equation:

(197)=100+12(5)+5(5)+7S+5(3)-8(3)

After simplification:

197=100+60+25+7S+15-24

We can add/subtract the constants:

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We will add/subtract the constants:

197=176+7S

We will subtract 176 from both sides of the equation to cancel it out and isolate 7S:

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3=S or S=3 with the symmetric property of Equality applied.

Therefore, he sold 3 pairs of shorts


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