3-D prosthetics would most likely be the answer, also, don’t copy links it’s most likely not the answer anyways.
        
             
        
        
        
Create an adjustment layer and create a hue and saturation layer. You'll see sliders so adjust them to your liking. next select a layer mask and fill it will black. then select which areas you want to darken and use the wand tool. Apply a gradient mask if you want. 
 
        
             
        
        
        
Yes insurance can help you
        
                    
             
        
        
        
Answer:
The control loop responds to
the overcharged VOUT with a skipped pulse to
regulate VOUT to the correct DC voltage. Other
converters may respond differently when the
minimum on-time is violated. For example, the
fSW may begin to decrease or VOUT may become
regulated to a higher voltage
Explanation:
 If you are trying to make a loop run a certain number of time in Python, then...
To repeat something a certain number of times, you may:
1. Use range or xrange for i in range(n): # do something here.
2. Use while i = 0 while i < n: # do something here i += 1.
3. If the loop variable i is irrelevant, you may use _ instead for _ in range(n): # do something here _ = 0 while _ < n # do something here _ += 1.
 
        
             
        
        
        
Answer:
-     public static String bothStart(String text1, String text2){
-         String s = "";
- 
-         if(text1.length() > text2.length()) {
-             for (int i = 0; i < text2.length(); i++) {
-                 if (text1.charAt(i) == text2.charAt(i)) {
-                     s += text1.charAt(i);
-                 }else{
-                     break;
-                 }
-             }
-             return s;
-         }else{
-             for (int i = 0; i < text1.length(); i++) {
-                 if (text1.charAt(i) == text2.charAt(i)) {
-                     s += text1.charAt(i);
-                 }else{
-                     break;
-                 }
-             }
-             return s;
-         }
-     }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13). 
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop. 
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).