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Anestetic [448]
3 years ago
13

5x + 5x + 2 + 6 equals 6x + 4 + 3xplz show steps I will give you a thankyou​

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0
^^^^^ that is the correct answer
amid [387]3 years ago
3 0
5x + 5x + 2 + 6 = 6x + 4 + 3x \\ 10x + 8 = 9x + 4 \\ 10x - 9x = 4 - 8 \\ x = - 4

HOPE THIS WILL HELP YOU
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Anyone who answers this correctly I WILL GIVE U A SUPER THANKS
Inga [223]

Answer:

25

Step-by-step explanation:

4x+8+72=180

4x+80=180

180-80=100

100/4=25

x=25

3 0
3 years ago
Wrench sets designed for SI bolts often include wrenches at 1 mm increments while wrench sets designed for imperial bolts often
juin [17]
So 5/8 inches to milimeters
we know that 1 in=2.54 cm so
5/8 in times 2.54= 1.5875 cm
1 cm=10 mm
1.5875 cm times 10=15.875mm aprox 16 mm, but best to go smaller since it won't fit if bigger

answer: 16mm (my recomendation would be 15mm)
3 0
3 years ago
9. Evaluate (-7) -10 ÷ (-28)-10<br> pls solve fast
Juli2301 [7.4K]

Answer:

17/38 or ≈ 0.45

Step-by-step explanation:

(-7) -10 / (-28)-10

= -17 / -38

= 17/38

You can keep the answer in fraction as 17/38 or ≈ 0.45

Hope this help you :3

7 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Which is the best estimate of 47 to the nearest tenth?i
juin [17]

Answer:

<h2>47.0</h2>

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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