Can someone help me with this please
1 answer:
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
=
+
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)
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Answer:
<h2>Step-by-step explanation:
Solve the equation for y by moving 'x' to R.H.S and changing its sign
Substitute the given value of y into the equation 5x + y = 28
Solve the equation for x
Collect like terms
Move constant to R.H.S and change its sign
Subtract the numbers
Divide both sides of the equation by 4
Calculate
Reduce the numbers with 2
Now, substitute the given value of x into the equation y = 2 - x
Solve the equation for y
The possible solution of the system is the ordered pair ( x , y )
<h2>-------------------------------------------------------------
Let's check if the given ordered pair is the solution of the system of equation:
plug the value of x and y in both equation
Simplify the equalities
Since , all of the equalities are true, the ordered pair is the solution of the system.
Hope this helps....
Best regards!!