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Vlad1618 [11]
3 years ago
13

The height (h), in feet, of a balloon is calculated by using the equation h equals 3t + 2 where t is the time,in seconds. What i

s the height of ballon after 30 seconds?
Mathematics
1 answer:
navik [9.2K]3 years ago
4 0
ANSWER: 92

EXPLANATION:
You plug in 30 where t us and solve.
3(30)+2=92
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Katyanochek1 [597]

Answer:

16

Step-by-step explanation:

8 0
2 years ago
Find the equation of the line with slope = 6 and passing through (6,43). Write your equation in the form y = m x + b .
gayaneshka [121]

Answer:

y = 6x + 7.

Step-by-step explanation:

Using the point-slope form of a line

y - y1 = m(x - x1)

m = 6, x1 = 6 and y1 = 43:

y - 43 = 6(x - 6)

y - 43 = 6x - 36

y = 6x - 36 + 43

y = 6x + 7.

5 0
3 years ago
Find the slope of the line going through the points (-5,-7) and (0,13)
Gre4nikov [31]

Answer:

slope=  4

Step-by-step explanation:

rise=20 run= 5    divide =4

6 0
3 years ago
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
How do i solve 1/2 × 3/7how do I solve one third of 3/7 <br><img src="https://tex.z-dn.net/?f=%201.5%20%5Ctimes%203.7" id="TexFo
Andrews [41]

1) \frac{1}{2}\,X\,\frac{3}{7}=\frac{3}{14}

2)  \frac{1}{3}\,X\,\frac{3}{7}=\frac{1}{7}

3)   1.5 \times 3.7\\=5.55

Step-by-step explanation:

We need to solve following expressions.

1) \frac{1}{2}\,X\,\frac{3}{7}

We need to multiply numerator with numerator and denominator with denominator

Solving:

\frac{1}{2}\,X\,\frac{3}{7}\\=\frac{3\,X\,1}{2\,X\,7}\\=\frac{3}{14}

It cannot be further simplified so,  \frac{1}{2}\,X\,\frac{3}{7}=\frac{3}{14}

2) one third of 3/7

one third stands for 1/3

Now solving:

\frac{1}{3}\,X\,\frac{3}{7}

We need to multiply numerator with numerator and denominator with denominator

\frac{1}{3}\,X\,\frac{3}{7}\\=\frac{3\,X\,1}{3\,X\,7}\\=\frac{3}{21}\\=\frac{1}{7}

It cannot be further simplified so,  \frac{1}{3}\,X\,\frac{3}{7}=\frac{1}{7}

3) 1.5 \times 3.7\\

In this question we have to multiply 1.5 with 3.7

1.5 \times 3.7\\=5.55

So, 1.5 \times 3.7\\=5.55

Learn More:

You can find more information about multiplication of fractions at:

brainly.com/question/2456302

brainly.com/question/2166248

Keywords: fractions, multiplication

#learnwithBrainly

5 0
3 years ago
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