<span>3 black ribbons and 12 green ribbons so P(</span><span>Lila selects a black ribbon)=3/(3+12) =1/5 </span>2 black ribbons and 12 green ribbons left P(<span>Jessica selects a green ribbon)=12/(12+2) </span>=6/7
so P(<span>Lila selects a black ribbon and Jessica selects a green ribbon) </span>=1/5*6/7 =6/35
