{(3x)}^{2}-2(3x)(5)+{5}^{2}
−2(3x)(5)+5
2
{(3x-5)}^{2}
Answer:
Step-by-step explanation:
scam . smď
CotR = -√3
In the 4th quadrant, sin is negative;
Since Cos R = √3/2,
Adjacent = √3
Hypotenuse = 2
Get the opposite;
opp^2 = 2^2 -(√3)^2
opp^2 = 4 - 3
opp^2 = 1
Opp = 1
Get sinR
Sin R = opp/hyp
SinR= -1/2
CotR = cosR/sinR
CostR = (√3/2)/(-1/2)
CotR = √3/2* -2/1
D-6/25
x = 3 ±
x² - 6x - 4 = 0 ( add 4 to both sides )
x² - 6x = 4
To complete the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(- 3)x + 9 = 4 + 9
(x - 3)² = 13 ( take square root of both sides )
x - 3 = ± ( add 3 to both sides )