We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc. For this type of problem you use the "n choose k" formula...
n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..
In this case:
20!/(10!(20-10)!)
20!/(10!*10!)
184756
Answer:
Where are the statements?
Step-by-step explanation:
Answer:
she need to buy 9 packs
Step-by-step explanation:
C = 2πr
= 2·3.14·14
= 87.92 m
she need to buy 9 packs
Answer:
B because u will have to first open the bracket according to BODMAS: bracket of division multiplication addition and subtract trust me before solving something like this use this <u>BODMAS</u>
