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Veseljchak [2.6K]
3 years ago
8

Can somebody please answer -5.3 + 9.8?

Mathematics
2 answers:
Slav-nsk [51]3 years ago
6 0

Answer:

4.5

Step-by-step explanation:

alexgriva [62]3 years ago
5 0

Answer:

4.5

Step-by-step explanation:

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Jillian rolled a number cube 360 times. About how many times do you expect her to roll a 2
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Answer: If it is split by equal sections then the answer Would be <u>60</u>

<em><u>Give Brainliest plz</u></em>

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3 years ago
If sine ⁡theta equals negative 8/17 and the terminal side of theta lies in quadrant IV, find cosine ⁡ theta .
Lelechka [254]
\sin^2\theta+\cos^2\theta=1\implies \cos\theta=\pm\sqrt{1-\sin^2\theta}

Since \sin\theta=-\dfrac8{17}, it follows that

\cos\theta=\pm\sqrt{1-\dfrac{64}{289}}=\pm\sqrt{\dfrac{225}{289}}=\pm\dfrac{15}{17}

where the sign depends on the location of the terminal side of the angle. Since the terminal side lies in the fourth quadrant, that means the cosine of the angle is positive, so

\cos\theta=\dfrac{15}{17}
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4 years ago
Stephen collected 12 more coins than Sariyah. How many coins Sariyah collect?
Komok [63]
How many coins do they have in all?
6 0
3 years ago
Read 2 more answers
What are the LCM of 24 and 30?
Alla [95]

The LCM of 24 and 30 is 120.

8 0
4 years ago
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The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
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