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kramer
3 years ago
15

red roses cost $3 each . Pink roses cost $2 each . A man buys 24 flowers for his wife with some pink roses and the rest red rose

s. The total cost of the flowers is $68 . Write a system of equations to model this situation and use the equation to determine how many red and how many pink roses he bought
Mathematics
1 answer:
katen-ka-za [31]3 years ago
3 0
20 red roses and 4 pink roses
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1/3v= -5 What is the value if v?
beks73 [17]

Given:

\frac{1}{3}v=-5

To get rid of the fraction, we can multiply both sides by the denominator, which is 3. This will cancel the fraction:

3(\frac{1}{3}v)=3(-5)

We are left with:

v=-15

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Step-by-step explanation:

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If the supplement of an angle is two-third of itself ,then its supplement is
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( 'x' is not 144 .)
 
The supplement of an angle is (180 - x) .
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180 - x = 2/3 x

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540 - 3x = 2x

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3 years ago
If f(x)=2x^3-6x^2-16x-20f(x)=2x *3 −6x *2−16x−20 and f(5)=0, then find all of the zeros of f(x)f(x) algebraically.
mihalych1998 [28]

The zeros of the cubic function f(x) = 2x³ - 6x² - 16x - 20 are given as follows:

x = 5, x = -1 + i, x = -1 - i.

<h3>How to obtain the solutions to the equation?</h3>

The equation is defined by the rule presented as follows:

f(x) = 2x³ - 6x² - 16x - 20.

One solution for the equation is given as follows:

x = 5.

Because f(5) = 0.

Then (x - 5) is a linear factor of the function f(x), which can be written as follows:

2x³ - 6x² - 16x - 20 = (ax² + bx + c)(x - 5).

This is because the product of a linear function and a quadratic function results in a cubic function.

Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

2x³ - 6x² - 16x - 20 =  = ax³ + (b - 5a)x² + (c - 5b)x - 5c.

Then these coefficients are obtained comparing the left and the right side of the equality as follows:

  • a = 2.
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Hence the equation is:

2x² + 4x + 4.

Using a quadratic equation calculator, the remaining zeros are given as follows:

  • x = -1 + i.
  • x = -1 - i.

More can be learned about the solutions of an equation at brainly.com/question/25896797

#SPJ1

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