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3 years ago

10

The lines of the equations are parallel, perpendicular, or neither. y = 2x + 3 y = 2x 1)parallel

1 answer:

faltersainse [42]3 years ago

7 0

They are both of the form y = mx + b where m = slope

m = 2 for both so they are parallel

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Can someone help me please.

34kurt

Answer:

c ?

Step-by-step explanation:

7 0

3 years ago

23,681,714 rounded to the nearest million

Katena32 [7]

24,000,000 because 600,000 is more than 1/2 1,000,000 so you round up.

5 0

3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Fiesta28 [93]

<h2>For x=2</h2>

$- 10(2) + y = 4$

$- 20 + y = 4$

$y = 24$

<h2>For x=1</h2>

$- 10( 1) + y = 4$

$- 10 + y = 4$

$y = 14$

<h2>For x=0</h2>

$- 10(0) + y = 4$

$0 + y = 4$

$y = 4$

<h2>For x=-1</h2>

$- 10( - 1) + y = 4$

$10 + y = 4$

$y = - 6$

<h2>For x=2</h2>

$- 10( - 2) + y = 4$

$20 + y = 4$

$y = - 16$

8 0

2 years ago

Read 2 more answers

Choose the correct description of the graph of the compound inequality x − 1 less than or equal to 9 or 2x greater than or equal

DerKrebs [107]

X - 1 < = 9 or 2x > = 24
x < = 9 + 1 x > = 24/2
x < = 10 x > = 12

closed circle on 10, shaded to the left
closed circle on 12, shaded to the right

________10_______12__________
<====X X======>
the X represents closed circles

8 0

3 years ago

zubka84 [21]

Answer:

See Explanation Below

Step-by-step explanation:

Given

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx.cos x.$

Required

Prove

To start with; we open the bracket on the left hand side

$(sin x - cos x)^2 = (sin x - cos x)(sin x - cos x)$

$(sin x - cos x)^2 = (sin x )(sin x - cos x)- (cos x)(sin x - cos x)$

$(sin x - cos x)^2 = sin^2 x -sinx cos x - sin xcos x + cos^2 x$

$(sin x - cos x)^2 = sin^2 x -2sinx cos x + cos^2 x$

Reorder

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

From trigonometry;

$sin^2x + cos^2x = 1$

So;

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

becomes

$(sin x - cos x)^2 = 1 - 2sinx cos x$

Also from trigonometry;

$sec^2x - tan^2x = 1$

So,

$(sin x - cos x)^2 = 1 - 2sinx cos x$

becomes

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx cos x$

Proved

3 0

3 years ago