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stira [4]
3 years ago
11

What times what equals 200.

Mathematics
2 answers:
olganol [36]3 years ago
7 0
Many things-

1x200
2x100
4x50
5x40
10x20

It is like listing the multiples of 200!


photoshop1234 [79]3 years ago
3 0
100 x 2 
25 x 8
200 x 1
10 x 20
etc...
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Colt1911 [192]

Answer:

line of best fit: y = -2.9114x + 46.569

Step-by-step explanation:

Plugging in your table into Excel, it turns out that y = -2.9114x + 46.569  provides a better fit of the data points into the line.  Please see the attached image for details.

Hope this helps.

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3 years ago
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kirill115 [55]

Answer:

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Step-by-step explanation:

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2 years ago
The diagonals of a kite are 22 feet and 33 long. what is the area ?
Goshia [24]

Answer:

A=363

Step-by-step explanation:

To solve the area of a kite you use

a =  \frac{pq}{2}

So 22×33=726 then divide that by 2 and you get 363.

7 0
3 years ago
According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var
-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

A)

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.7

10.9

11.2

11.5

11.8

n=10(even)

Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : \sqrt{\frac{\sum(x-\bar{x})^2}{n}}

Standard deviation :\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}

Standard deviation :0.89916

C)

8.3

,10.3

,10.5

,10.6

,10.7

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range :(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0
3 years ago
At that velocity voyager 1 would have traveled 547,500,000 kilometers in a year. Whats that in scientific notation ?
andrey2020 [161]

Answer: 5.475 x 10^8

Step-by-step explanation: The number has to be in between 1 and 10 so you move your decimal as many times as you need to. In this situation it is 8, so that is your power

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