Assuming that the affection is a recessive trait caused by a single diallelic gene, the percentage of the population that possess the heter0zyg0us advantage is 32%.
<h3>
Available data</h3>
- 1000 of African people population
- 4% of the population is born with sickle cell anemia
100% of the population -------------------- 1000 individuals
4% of the population with anemia------- X = (4 x 1000) / 100 = 40
0.04 is the frequency of individuals with sickle cell anemia.
Assuming that the affection is a recessive trait caused by a single diallelic gene, we can get the allelic frequency as follows.
- The genotypic frequency is q² = 0.04
- The allelic frequency is q = √0.04 = 0.2
Having the recessive allelic frequency, we can get the dominant allelic frequency, by clearing the following equation,
p + q = 1
p = 1 - q
p = 1 - 0.2
p = 0.8
So, the allelic frequencies are
p = 0.8
q = 0.2
To get the heter0zyg0us frequency, we just need to replace the values
2pq = 2 x p x q = 2 x 0.2 x 0.8 = 0.32
The frequency of the heter0zyg0us genotype is 0.32 = 32%.
32% of the population possess the heterozygous advantage.
You can learn more about Hardy-Weinberg equilibrium at
brainly.com/question/8667324
