Question

Hardy Weinberg Practice Problems To demonstrate your understanding of the Hardy-Weinberg equilibrium, answer each question carefully. When you are finished, submit your completed assignment. 1. In a 1000 of African people, 4% of the population is born with sickle cell anemia. What percentage of the population possess the heterozygous advantage

Answer 1

Assuming that the affection is a recessive trait caused by a single diallelic gene, the percentage of the population that possess the heter0zyg0us advantage is 32%.

Available data

• 1000 of African people population
• 4% of the population is born with sickle cell anemia

100% of the population -------------------- 1000 individuals

4% of the population with anemia------- X = (4 x 1000) / 100 = 40

0.04 is the frequency of individuals with sickle cell anemia.

Assuming that the affection is a recessive trait caused by a single diallelic gene, we can get the allelic frequency as follows.

• The genotypic frequency is q² =  0.04

• The allelic frequency is q = √0.04 = 0.2

Having the recessive allelic frequency, we can get the dominant allelic frequency, by clearing the following equation,

p + q = 1

p = 1 - q

p = 1 - 0.2

p = 0.8

So, the allelic frequencies are

p = 0.8

q = 0.2

To get the heter0zyg0us frequency, we just need to replace the values

2pq = 2 x p x q = 2 x 0.2 x 0.8 = 0.32

The frequency of the heter0zyg0us genotype is 0.32 = 32%.

32% of the population possess the heterozygous advantage.

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