Ask question

Ask question

All categories

4 years ago

6

The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.

Which best explains whether or not the truck can pass safely under the bridge?

1 answer:

Nutka1998 [239]4 years ago

4 0

It would not pass under the bridge because ig you divide 162 by 12 it would equal 13.5

You might be interested in

Which expression is equivalent to 4+x+x+2x+5+3+x?

AysviL [449]

$\longrightarrow{\blue{B.\:5x\:+\:12}}$

$\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}$

$4 + x + x + 2x + 5 + 3 + x$

Combining like terms, we have

$= x + x + 2x + x + 4 + 5 + 3$

Next, add them

$= 5x + 12$

Therefore, '' $\sf\pink{4 + x + x + 2x + 5 + 3 + x}$ " is equivalent to " $\sf\purple{5x\:+\:12}$ ."

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}$

4 0

3 years ago

Read 2 more answers

Solve the inequality 1/4c<4

Softa [21]

Answer:

Multiply each term by 4 and simplify.

Inequality Form:

c < 16

Interval Notation:

( − ∞ , 16 )

Step-by-step explanation:

3 0

3 years ago

What is the work and answer to 16.8÷0.8

melamori03 [73]

Hi

16.8/0.8 = 168/8 = 21

168 |__8__
-16 21
------
08
- 08
------
00

Answer: 21

3 0

3 years ago

Read 2 more answers

The function f(x) = 6x + 8 is transformed to function g through a horizontal stretch by a factor of 5. What is the equation of f

Vsevolod [243]

Answer:

$g(x) = \frac{6}{5}x + 8$

Step-by-step explanation:

Given

$f(x) = 6x + 8$

$k = 5$ --- horizontal stretch factor

Required

Find g(x)

When a function is stretched horizontally by k, the resulting function will be:

Rule: $g(x) = f(\frac{1}{k}x)$

So, we have:

$g(x) = f(\frac{1}{5}x)$

Solve for: $f(\frac{1}{5}x)$

$f(\frac{1}{5}x) = 6 * \frac{1}{5}x + 8$

$f(\frac{1}{5}x) = \frac{6}{5}x + 8$

Recall that:

$g(x) = f(\frac{1}{5}x)$

$g(x) = \frac{6}{5}x + 8$

5 0

3 years ago

Read 2 more answers

Number one solve sin l and tan n cos l and sin n

const2013 [10]

Sin L= 3/5

Tan N= 3/5

Cos L=4/5

Sin N=4/5

5 0

3 years ago