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Jobisdone [24]
3 years ago
15

A student is decorating a circular picture frame that has a diameter of 8 inches. How many inches of fabric will the student nee

d to go completely around the outside of the frame?​

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Circumference is equal to \pi d

C=\pi d

C=\pi \times 8

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Solve this 11 - 3 × 4 + 3
scoray [572]

BEDMAS

3x4 = 12

11 - 12 + 3

11 - 12 = -1

-1 + 3 = 2

3 0
3 years ago
Read 2 more answers
Determine if p2+14p+49 is a perfect trinomial
shusha [124]

Answer:

Step-by-step explanation:

p²  + 14p + 49 = p² + 2 * 7p + 7²

Comparing with a² + 2ab + b²,

a= p and b = 7

So 2ab = 2*p*7 = 14 p

So, p²  + 14p + 49 is a perfect trinomial

4 0
3 years ago
22) Two students are taking a math test. After 5 minutes, one student is done 1/3 and the
Afina-wow [57]

Answer:

  • 1/12

Step-by-step explanation:

<u>We need to find the difference in progress:</u>

  • 1/3 - 2/8 =
  • 1/3 - 1/4 =
  • 4/12 - 3/12 =
  • 1/12

The first student is 1/12 ahead

3 0
2 years ago
Can you please help me fill in the blanks
masha68 [24]

Answer:

Domain = [-2, 2) range = [1, 2) y intercept = (0, 1) positive interval = [0, 2) average rate of change = 1

Step-by-step explanation:

Domain is all possible x values, numbers that are included or have a closed circle get a square bracket [], numbers not included or with an open circle get a parenthesis ()

range is all possible y values

y intercept is what y  when x is 0

positive interval is where is positive

3 0
3 years ago
The area of the face of a cube is 9 square centimeters. Use 9 of these cubes to make a rectangular prism. What is the volume of
Vika [28.1K]

Answer:

243 cm^3

Step-by-step explanation:

The faces of a cube are squares.

A = s^2

s^2 = 9 cm^2

s = 3 cm

The side of the square is the edge of the cube and is 3 cm.

V = s^3

V = (3 cm)^3 = (3 cm)(3 cm)(3 cm) = 27 cm^3

The volume of one cube is 27 cm^3.

The volume of 9 cubes is 9 * 27 cm^3 = 243 cm^3

Answer: 243 cm^3

5 0
2 years ago
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