Hi there!
Let th' two number be ' a ' and ' b ' [ a > b ]
According to th' question :-
→ The largest of two numbers is 12 more than the smaller number.
a = 12 + b ---(i)
→ Sum of the two numbers is 74.
a + b = 74
b = 74 - a ---(ii)
Substitute th' value of ' b in Eqn. :-
a = 12 + (74 - a)
a = 86 - a
a + a = 86
2a = 86
a =

= 43
Now,
Substitute th' value of ' a ' in Eqn. (ii)
b = 74 - b
b = 74 - 43
b = 31
Hence,
The required answer is :-
• The smaller number is 31
• The largest number is 43
~ Hope it helps!
TRAVIS AND PAULA SPEND FOR LUNCH 7.50+5.25=12.75 DOLLARS
WE NEED TO FIND OUT HOW MUCH IS 1% OUT OF 12.75 WHICH IS
12.75/100=.1275
.1275*15=1.91 TIP LEFT
12.75+1.91=14.66
x=1, y=2
Solve the following system:
{y = 5 - 3 x5 x - 4 y = -3
Substitute y = 5 - 3 x into the second equation:
{y = 5 - 3 x5 x - 4 (5 - 3 x) = -3
5 x - 4 (5 - 3 x) = (12 x - 20) + 5 x = 17 x - 20:{y = 5 - 3 x17 x - 20 = -3
In the second equation, look to solve for x:{y = 5 - 3 x17 x - 20 = -3
Add 20 to both sides:{y = 5 - 3 x17 x = 17
Divide both sides by 17:{y = 5 - 3 xx = 1
Substitute x = 1 into the first equation:{y = 2x = 1
Collect results in alphabetical order:Answer: {x = 1 y = 2
7.2
Work: 45% x 16=
(45/100) x 16=
(45x16) / 100=
720/100=
7.2
As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
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