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lana66690 [7]
3 years ago
9

Please help me out with this

Mathematics
1 answer:
nignag [31]3 years ago
3 0
P(score > 334) ≈ .0227501319

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20 points! Write an exponential function in the form y=ab^x that goes through points (0, 8) and (2, 200)
alexandr402 [8]

Answer:

y=8(5)^x

Step-by-step explanation:

We want an exponential function that goes through the two points (0, 8) and (2, 200).

Since a point is (0, 8), this means that y = 8 when x = 0. Therefore:

8=a(b)^0

Simplify:

a=8

So we now have:

y = 8( b )^x

Likewise, the point (2, 200) tells us that y = 200 when x = 2. Therefore:

200=8(b)^2

Solve for b. Dividing both sides by 8 yields:

b^2=25

Thus:

b=5

Hence, our exponential function is:

y=8(5)^x

4 0
3 years ago
Read 2 more answers
Find the measure of the missing angles.
Yuri [45]

Answer:

d = 102° , e = 56° , f = 22°

Step-by-step explanation:

d and 102° are vertically opposite angles and congruent , so

d = 102°

e and 56° are vertically opposite angles and are congruent , so

e = 56°

f, d and e lie on a straight line and sum to 180° , then

f + d + e = 180° , that is

f + 102° + 56° = 180°

f + 158° = 180° ( subtract 158° from both sides )

f = 22°

3 0
3 years ago
It takes one examiner 36 hours to mark 70 exam papers. How long would it take 6 examiners to mark 70 papers?
Orlov [11]

Answer:

36 divided by 6 is 6

Step-by-step explanation:

idk if im right i j wokeup lol

3 0
3 years ago
What is the unit rate for a relationship A (the table)? (do not include units for this one)
kobusy [5.1K]

Answer:

it is per 1

Step-by-step explanation:

3 0
1 year ago
-1/3 + (-7/4)<br> pls help
djverab [1.8K]

Answer:

  -25            

 ——— = -2.08333

    12  

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           4

Equation at the end of step  1  :

       1           7

 (0 -  —) +  (0 -  —)

       3           4

Step  2  :

           1

Simplify   —

           3

Equation at the end of step  2  :

       1     -7

 (0 -  —) +  ——

       3     4

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       3

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

3 1 0 1

2 0 2 2

Product of all

Prime Factors  3 4 12

     Least Common Multiple:

     12

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      -1 • 4

  ——————————————————  =   ——————

        L.C.M               12  

  R. Mult. • R. Num.      -7 • 3

  ——————————————————  =   ——————

        L.C.M               12  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

-1 • 4 + -7 • 3     -25

———————————————  =  ———

      12            12

Final result :

 -25            

 ——— = -2.08333

 12            

Processing ends successfully

plz mark me as brainliest :)

7 0
3 years ago
Read 2 more answers
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