Is it subtract by 2? So I think it would be 27,25,23,21, 19
Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean,
= 1.3 cm and Standard deviation,
= 0.01 cm
Also, since distribution is normal;
Z =
~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P(
<
) = P(Z < 3) = 0.99865
P(X <= 1.27) = P(
<
) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
Step-by-step explanation:
a) Desiree is correct 630000÷70=900
Answer:
78.54in²
Step-by-step explanation:
i used the formula
Answer:
f (x) = 3(x+5) (x+2) / (x-2) (x+5)
Step-by-step explanation: