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2 years ago

How to bypass school chromebook and download games?

Mathematics

2 answers:

charle [14.2K]2 years ago

8 0

Answer:

chromebooks cant download games with or without a school filter

however, if you search "unblocked games" you might find some not blocked games

Step-by-step explanation:

sammy [17]2 years ago

5 0

Answer:

You can . , ... : ' , .

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What is the radius of a sphere with the volume of 113.04 in.³

Nimfa-mama [501]

3 is the answer! Have a nice day!

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2 years ago

Does this equation have exactly one solution

Alex73 [517]

Answer:

$13x + 7 = 9x - 33 + 4x \\ 7 + 33 = 13x - 13x \\ \\ 40 = 0 \\ \\ no$

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2 years ago

If 3 3\4lbs of candy cost $20.25, how much would 1 lb of candy cost

r-ruslan [8.4K]

3 3/4 =3.75
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2 years ago

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

2 years ago

0.76 as a mixed number

melisa1 [442]

Answer:

19/25

Step-by-step explanation:

6 0

2 years ago