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nordsb [41]
3 years ago
13

What happens when variables in programming are not properly initialized? answers?

Computers and Technology
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0
Errors in compilation happen, or it runs but then doesn't recognize the input. Also you can't transform into other types of variables.
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Tanya [424]

Answer:

Answer explained below

Explanation:

Below is the code for Greedy change algorithm in C++. Please let me know what  does c ,k and represent in the question. so that i can update according to requirement

#include <bits/stdc++.h>  

using namespace std;  

int deno[] = { 1, 3,9,27,81 };  

int n = sizeof(deno) / sizeof(deno[0]);  

void findMin(int V)  

{  

   // Initialize result  

   vector<int> ans;  

   // Traverse through all denomination  

   for (int i = n - 1; i >= 0; i--) {  

       // Find denominations  

       while (V >= deno[i]) {  

           V -= deno[i];  

           ans.push_back(deno[i]);  

       }  

   }  

   // Print result  

   for (int i = 0; i < ans.size(); i++)  

       cout << ans[i] << " ";  

}  

int main()  

{  

   int n = 38;  

   cout << "Following is minimal number of change for " << n << ": ";  

   findMin(n);  

   return 0;  

}

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4 years ago
SOMEONE PLEASE HELP ME PLEASE!!!!!
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Answer:

The last one.

Explanation:

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Hope this was helpful! <3
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