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3 years ago

Show all steps used to solve the problem 4x+6<-6

Mathematics

1 answer:

mel-nik [20]3 years ago

4 0

The answer is x<-3

Step-by-step explanation:

4x+6<-6

-6 -6

4x>-12

÷4x. ÷4×

x<-3

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A toy rocket is launched from the top of a building 135 feet tall at an initial velocity of 167 feet per second. Give the functi

Cerrena [4.2K]

Answer:

h(t) = = -16t^2 + 167t + 135

Step-by-step explanation:

This is an equation of motion of an object umder a constant acceleration(here it is the acceleration due to gravity);

h(t) = = -16t^2 + 167t + 135.

Note: t is the time in seconds and h is the height in feet at time t.

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3 years ago

Is -41 a rational number

kiruha [24]

A rational number can be written in the form a/b where b≠0

-41=-41/1
it is rational
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3 years ago

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Dennis_Churaev [7]

Answer:

Step-by-step explanation:

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2 years ago

What is the degree of the polynomial function shown in the graph?

dusya [7]

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3 years ago

Read 2 more answers

Here is a triangular pyramid and its net.

galben [10]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

8 0

2 years ago