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WARRIOR [948]
3 years ago
6

1+1(2)-5+96-4(67+9)+59+10

Mathematics
1 answer:
faltersainse [42]3 years ago
7 0
The answer would be -141.
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Hello there! How to find the probability? See picture! Thank you and please show your work!
german

Answer:

  0.8914

Step-by-step explanation:

You want to find the z-values associated with the x-values:

 z = (x -μ)/σ

 z1 = (57 -90)/12 = -2.75

 z2 = (105 -90)/12 = 1.25

Look up these values in a probability table and find the difference of the table values.

 p(z < z1) ≈ 0.00298 . . . . from a table or calculator

 p(z < z2) ≈ 0.89435 . . . . from a table or calculator

p(57 < x < 105) ≈ 0.89435 -0.00298 = 0.89137 ≈ 0.8914

8 0
4 years ago
Sophie could $330 in a savings account at a simple interest rate of 4% per year. Avi put $290 in a savings account at a simple i
worty [1.4K]
Sophie would’ve earned more
She would’ve earned $37 more

Calculations:
Sophie:
$330(1+4%*2)
=$356
Simple interest: $356-$330
=$26

Avi:
$290(1+5%*2)
=$319
Simply interest: $319-$290
=$29

$29-$26
=$3
8 0
4 years ago
why did Frederick Douglass Narrative and Harriet Beecher Stowe’s Uncle Tom’s Cabin helped build social support for abolition and
Tema [17]
To attempt to end slavery is what I would think, maybe to show that they are humans themselves and treating them this way is very unfair.
4 0
3 years ago
Work out 3x6-2x4 so I can get the answer
MAXImum [283]

If expression is like this :

3x^6 - 2x^4

x^4 (3x^2 - 2)

_______________________

If expression is like this :

3×6-2×4

18 - 8

10

4 0
1 year ago
Am I correct on question #6?
pashok25 [27]

Option A:

\tan(105^\circ)=-(2+\sqrt{3})

Solution:

<u>To evaluate tan(105)°:</u>

105° can be written as sum of 60° and 45°.

tan(105)° = tan(45 + 60)°

Using the summation identity:

$\tan (x+y)=\frac{\tan (x)+\tan (y)}{1-\tan (x) \tan (y)}

$\tan \left(105^{\circ}\right)=\frac{\tan \left(45^{\circ}\right)+\tan \left(60^{\circ}\right)}{1-\tan \left(45^{\circ}\right) \tan \left(60^{\circ}\right)}

We know that, tan(45)° = 1 and tan(60)° = √3

Substitute this in the above equation.

              $=\frac{1+\sqrt{3}}{1-1 \cdot \sqrt{3}}

              $=\frac{1+\sqrt{3}}{1-\sqrt{3}}

To rationalize the denominator multiply by the conjugate \frac{1+\sqrt{3}}{1+\sqrt{3}}.

              $=\frac{(1+\sqrt{3})(1+\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})}

Using exponent formula: a^{b} \cdot a^{c}=a^{b+c} and (x-y)(x+y)=x^2-y^2

              $=\frac{(1+\sqrt{3})^2}{(1^2-(\sqrt{3})^2)}

Using exponent formula: (a+b)^{2}=a^{2}+2 a b+b^{2}

              $=\frac{1^{2}+2 \cdot 1 \cdot \sqrt{3}+(\sqrt{3})^{2}}{1-3}

              $=\frac{4+2 \sqrt{3}}{-2}

              $=\frac{2(2+ \sqrt{3})}{-2}

              =-(2+\sqrt{3})

\tan(105^\circ)=-(2+\sqrt{3})

Hence option A is the correct answer.

6 0
4 years ago
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