1.sun
2.mercury
3.venus
4.earth
5.mars
6.jupiter
7.saturn
8.uranus
9.neptune
Answer:
g = 0.85 m
Explanation:
g =
were; g is the acceleration due to Earth's gravity, G is Newton's gravitation constant (6.674 x N), M is the mass of the earth (5.972 x kg), and h is the distance of meteoroid to the earth.
h = 3.40 x R
= 3.40 x 6371 km
h = 21661.4 km
= 21661400 m
Thus,
g =
=
= 0.84944
g = 0.85 m
The acceleration due to the Earth's gravitation is 0.85 m.
Resultant force (newton, N) = mass (kg) × acceleration (m/s2<span>)
Hope this helped :)</span>
The question is incomplete. The complete question is :
The pressure difference, Δp, across a partial blockage in an artery (called a stenosis) is approximated by the equation :
Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the artery diameter, the area of the unobstructed artery, and A1 the area of the stenosis. Determine the dimensions of the constants and . Would this equation be valid in any system of units?
Solution :
From the dimension homogeneity, we require :
Here, x means dimension of x. i.e.
So, dimensionless
So, and are dimensionless constants.
This equation will be working in any system of units. The constants and will be different for different system of units.
Answer:
4.56×10¯⁷¹ N
Explanation:
From the question given above, the following data were obtained:
Distance apart (r) = 1.10 m
Force (F) =?
NOTE:
Gravitational constant (G) = 6.67×10¯¹¹ Nm² /Kg²
Mass of electron = 9.1×10¯³¹ Kg
Mass of the two elections = M₁ = M₂ = 9.1×10¯³¹ Kg
Thus, we can obtain the force of attraction between the two elections as illustrated below:
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × (9.1×10¯³¹)² / (1.1)²
F = 4.56×10¯⁷¹ N
Thus, the force of attraction between the two elections is 4.56×10¯⁷¹ N