Question

6. A football is kicked with an initial speed of 10.2 m/s at an angle of 40.00 above the horizontal. It lands on the ground 2.12 s later. Determine the velocity of the football at the pinnacle of its trajectory.

Answer 1

Answer:

7.81 m/s

Explanation:

Given,

initial speed, u = 10.2 m/s

angle of inclination, θ = 40°

time, t = 2.12 s

Horizontal component of the velocity:

$u_x = u cos \theta$

$u_x = 10.2\times cos 40^0$

$u_x = 7.81 m/s$

In projectile motion horizontal component of the velocity remain same at every point because there is no acceleration.

So, Velocity at the Pinnacle is equal to 7.81 m/s