Question

Translate then solve the algebraic equation for the following problems:

Answer 1

Fourteen less than 5 times a number is 1. Identify the integer.
5x-14=1
5x=14+1
x=15/5
x=3
TO CHECK THE ANSWER INPUT THE VALUE IN THE PLACE OF X
5(3)-14=1
15-14=1
1=1. (BOTH SIDES EQUAL) ✔️

The sum of two consecutive integers is 139. Find the integers
(x) +(x+1)=139
x+x+1=139
2x=139-1
x=138/2
x=69
CHECK
69+69+1=139
138+1=139
139=139
(both sides equal) ✔️

Answer 2

Answer:

First, let's call the number we are looking for:  

n

Then, "four times a number" can be written as:  

4

n

Next, "Fourteen less than this" can be written as :  

4

n−14

Now, we can add "is six" to the expression to create the equation:

4

n−14=6

Step-by-step explanation:

Ten more than x x + 10

A number added to 5 5 + x

A number increased by 13 x + 13

5 less than 10 10 - 5

A number decreased by 7 x - 7

Difference between x and 3 x - 3

Difference between 3 and x 3 - x

Twice a number 2x

Ten percent of x 0.10x

Ten times x 10x

Quotient of x and 3 x/3

Quotient of 3 and x 3/x

Five is three more than a

number

5 = x + 3

The product of 2 times a

number is 10

2x = 10

One half a number is 10 x/2 = 10

Five times the sum of x and 2 5(x + 2)

Seven is greater than x 7 > x

Five times the difference of a

number and 4

5(x - 4)

Ten subtracted from 10 times a

number is

that number plus 5

10x - 10 = x

+ 5

The sum of 5x and 10 is equal

to the product of x and 15

5x + 10 =

15x

The sum of two consecutive

integers

(x) + (x + 1)

The sum of two consecutive

even integers

(x) + (x + 2)

The sum of two consecutive odd

integers