All categories

4 years ago

SOMEONE PLEASE HELP ASAP!! THANK YOU SO MUCH!!!

Biology

1 answer:

blsea [12.9K]4 years ago

7 0

1- B
2-B
3-C
4-B
5-A
6-A
I cant see the options for question 7, but here are the answers for 1-6. Hope they help!

You might be interested in

Helppppp boooo!!!!!

8090 [49]

By the first distance, I'd say Venus (0.72 AU)

By the second distance, I'd say it's Saturn (9.54 AU)

But you also say it has no visible rings so the answer is VENUS.

Hope it helped,

Happy homework/ study/ exam!

3 0

3 years ago

Read 2 more answers

A solute uses a protein channel to cross into or out of the cell. What

Natalija [7]

D, active transport because that protein uses atp to cross channels and active transportation is the only form of movement that’s used atp to move

6 0

4 years ago

Which phase occurs immediately after a full moon?

Rashid [163]

Waning gibbous

youre welcome

3 0

3 years ago

g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time

Elenna [48]

Answer:

a. 8.1 milligrams

b. 40.07 hours

c. 8.859 milligrams

Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

$A_{t}=10e^{-0.0173t}$

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

$A_{12}=10e^{-0.0173\times12}$

$A_{12}=10e^{-0.2076}$

= 10×0.81253

= 8.1 milligrams

b. In this part we have to calculate the time when A(t) = 5 milligrams

$5=10e^{-0.0173\timest}$

$\frac{5}{10}=e^{-0.0173t}$

0.5 = $e^{-0.0173t}$

Now we take natural log on both the sides of the equation.

ln(0.5) = ln( $e^{-0.0173t})$

-0.69314 = -0.0173t

t = $\frac{0.69314}{0.0173}$

t = 40.0658

≈ 40.07 hours

c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

$A_{7}=10e^{-0.0173\times7}$

$A_{7}=10e^{-0.1211}$

= 10×0.8859

= 8.859 milligrams

6 0

4 years ago

In the F2 generation of Mendel’s crosses

irina1246 [14]

In the f2 generation of mendel's crosses, all plants had the dominant trait,all plants had both the dominant and recessive alleles. one in four plants had two alleles for the recessive trait.

3 0

3 years ago