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3 years ago

What is the slope for the points (-1, 1) and (2, 3)?

Mathematics

1 answer:

zalisa [80]3 years ago

6 0

Answer:

slope is 0.6666666667

Step-by-step explanation:

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A farmer has 500 feet of fencing to enclose a rectangular

gizmo_the_mogwai [7]

Answer:

Becoming a square will cause in the sides to grow higher and become taller therefore.

Step-by-step explanation:

7 0

3 years ago

The equation that models this trip is T= 36x + 60 where T represents the total cost for the group to take the trip and X equals

Archy [21]

We are given

The equation that models this trip is T= 36x + 60

T represents the total cost for the group to take the trip and

X equals the number of people going

we know that

Domain is all possible values of x for which any function is defined

Since, number of people can neither be negative nor in decimals

so, x can not be negative or in decimals

now, we will check each options

option-A:

x=40

This is positive and whole number

so, this can be domain

so, this is TRUE

option-B:

x=60

This is positive and whole number

so, this can be domain

so, this is TRUE

option-C:

0< x< 40

It also includes decimals numbers

and we know that

x can not be in decimals

so, this is FALSE

option-D:

0< x< 39

It also includes decimals numbers

and we know that

x can not be in decimals

so, this is FALSE

4 0

3 years ago

Read 2 more answers

Find the value of each variable

aniked [119]

Answer:

Answer d)

$a= 10*\sqrt{3}$ $b=5*\sqrt{3}$ , $c=15$ , and $d=5$

Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

$b=10*sin(60^o)= 10*\frac{\sqrt{3} }{2} = 5*\sqrt{3}$

where we use the fact that the sine of 60 degrees can be written as: $\frac{\sqrt{3} }{2}$

We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

$d=10*cos(60^o)=10* \frac{1}{2} = 5$

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

$sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}$

where we used the value of the sine function of 30 degrees as one half: $\frac{1}{2}$

Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

$c=10*\sqrt{3} * cos(30^o)=10*\sqrt{3} *\frac{\sqrt{3} }{2} \\c= 5*3=15$