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agasfer [191]
3 years ago
12

On a ceiling, there were tiny droplets of blood less than 1 mm in diameter. The victim was lying in a pool of blood. No other ma

rks were found on the other walls. Which best explains the sequence of events?
The victim was shot with a gun from behind and collapsed on the floor beneath.

The victim shot himself in the mouth.

The victim was stabbed with a knife.

The victim was hit in the head with a blunt object.
Physics
2 answers:
telo118 [61]3 years ago
8 0

Answer: "On a ceiling, there were tiny droplets of blood less than 1 mm in diameter." this can discard the knife theory.

"No other marks were found on the other walls" this is an interesting part, because usually a bullet would leave a mark in the walls or the ceiling, and this is not the case here, so we also could the "shot from behind"

"The victim was lying in a pool of blood". A hit in the head, actually could cause a hemorrhage, and maybe also could spread the tiny droplets of blood, because they have 1mm diameter, they are really tiny . But the second option is the really more likely, the only problem here is that there are no marks of a bullet in the ceiling.

mylen [45]3 years ago
3 0
I believe the correct answer from the choices listed above is the second option. The statement that would best explain the sequence of events would be that the <span> victim shot himself in the mouth. Hope this answers the question. Have a nice day.</span>
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A screen is placed a distance dd to the right of an object. A converging lens with focal length ff is placed between the object
Elina [12.6K]

Answer:

2f

Explanation:

The formula for the object - image relationship of thin lens is given as;

1/s + 1/s' = 1/f

Where;

s is object distance from lens

s' is the image distance from the lens

f is the focal length of the lens

Total distance of the object and image from the lens is given as;

d = s + s'

We earlier said that; 1/s + 1/s' = 1/f

Making s' the subject, we have;

s' = sf/(s - f)

Since d = s + s'

Thus;

d = s + (sf/(s - f))

Expanding this, we have;

d = s²/(s - f)

The derivative of this with respect to d gives;

d(d(s))/ds = (2s/(s - f)) - s²/(s - f)²

Equating to zero, we have;

(2s/(s - f)) - s²/(s - f)² = 0

(2s/(s - f)) = s²/(s - f)²

Thus;

2s = s²/(s - f)

s² = 2s(s - f)

s² = 2s² - 2sf

2s² - s² = 2sf

s² = 2sf

s = 2f

8 0
3 years ago
Which phase of cell division results in the formation of 4 new haploid cells
Alexandra [31]
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-vf
7 0
4 years ago
Un camion de envios se encuentra detenido en una señal de pare, permitiendo que pase una ambulancia. Inicia su recorrido y al ca
Nesterboy [21]

Answer:

0.741\ \text{m/s}^2

Explanation:

v = Velocidad final = 40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2

La aceleración del camión en el primer intervalo de tiempo es 0.741\ \text{m/s}^2.

4 0
3 years ago
The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. The distance between the
Mama L [17]

Answer: (a) power output = 3.85×10²⁶W

(b). There is no relative change in power as it is independent from frequency

(c). 590 W/m²

Explanation:

given Radius between earth and sun to be = 1.50 × 10¹¹m

Intensity of the radiation from the sun measured on earth to be = 1360 W/m²

Frequency = 60 MHz

(a). surface area A of the sun on earth is = 4πR²

substituting value of R;

A = 4π(.50 × 10¹¹)² = 2.863 10²³×m²

A = 2.863 10²³×m²

now to get the power output of the sun we have;

<em>P </em>sun = <em>I </em><em>sun-earth </em><em>A </em><em>sun-earth</em>

where A = 2.863 10²³×m², and <em>I </em> is 1360 W/m²

<em>P </em>sun =  2.863 10²³ × 1360

<em>P </em>sun = 3.85×10²⁶W

(c). surface area A of the sun on mars is = 4πR²

now we substitute value of 2.28 ×10¹¹ for R sun-mars, we have

A sun-mars = 4π(2.28× 10¹¹)²

A sun-mars = 6.53 × 10²³m²

now to calculate the intensity of the sun;

<em>I </em><em>sun-mars = </em><em>P </em>sun / A sun-mars

where <em>P </em>sun = 3.85×10²⁶W and A sun-mars = 6.53 × 10²³m²

<em>I </em><em>sun-mars =  </em>3.85×10²⁶W / 6.53 × 10²³m²

<em>I </em><em>sun-mars = </em>589.6 ≈ 590 W/m²

<em>I </em><em>sun-mars = </em>590 W/m²

6 0
4 years ago
The loudness of sound is determined by what?
baherus [9]
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5 0
3 years ago
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