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agasfer [191]
3 years ago
12

On a ceiling, there were tiny droplets of blood less than 1 mm in diameter. The victim was lying in a pool of blood. No other ma

rks were found on the other walls. Which best explains the sequence of events?
The victim was shot with a gun from behind and collapsed on the floor beneath.

The victim shot himself in the mouth.

The victim was stabbed with a knife.

The victim was hit in the head with a blunt object.
Physics
2 answers:
telo118 [61]3 years ago
8 0

Answer: "On a ceiling, there were tiny droplets of blood less than 1 mm in diameter." this can discard the knife theory.

"No other marks were found on the other walls" this is an interesting part, because usually a bullet would leave a mark in the walls or the ceiling, and this is not the case here, so we also could the "shot from behind"

"The victim was lying in a pool of blood". A hit in the head, actually could cause a hemorrhage, and maybe also could spread the tiny droplets of blood, because they have 1mm diameter, they are really tiny . But the second option is the really more likely, the only problem here is that there are no marks of a bullet in the ceiling.

mylen [45]3 years ago
3 0
I believe the correct answer from the choices listed above is the second option. The statement that would best explain the sequence of events would be that the <span> victim shot himself in the mouth. Hope this answers the question. Have a nice day.</span>
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5 0
2 years ago
A cannon with a muzzle speed of 1 000 m/s is used to start an avalanche on a mountain slope. The target is 2 000 m from the cann
Nataliya [291]

Answer:

∅ = 89.44°

Explanation:

In situations like this air resistance are usually been neglected thereby making g= 9.81 m/s^{2}

Bring out the given parameters from the question:

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Target height (h) =  800 m

Projection angle ∅ = ?

Horizontal distance = V_{1x}tcos ∅     .......................... Equation 1

where V_{1x} = velocity in the X - direction

           t = Time taken

Vertical Distance = y = V_{1y} t - \frac{1}{2}gt^{2}        ................... Equation 2

Where   V_{1y} = Velocity in the Y- direction

              t  = Time taken

V_{1y} = V_{1}sin∅

Making time (t) subject of the formula in Equation 1

                    t = d/(V_{1x}cos ∅)

                      t = \frac{2000}{1000coso} = \frac{2}{cos0}  =    \frac{d}{cos o}             ...................Equation 3

substituting equation 3 into equation 2

Vertical Distance = d = V_{1y} \frac{d}{cos o} - \frac{1}{2}g\frac{2}{cos0}   ^{2}

                                  Vertical Distance = h = sin∅ \frac{d}{cos o} - \frac{1}{2}g\frac{2}{cos0}   ^{2}

  Vertical Distance = h = dtan∅   - \frac{1}{2}g\frac{2}{cos0}   ^{2}

  Applying geometry

                              \frac{1}{cos o} = tan^{2} o + 1

  Vertical Distance = h = d tan∅   - 2 g (tan^{2} o + 1)

               substituting the given parameters

               800 = 2000 tan ∅ - 2 (9.81)( tan^{2} o + 1)

              800 = 2000 tan ∅ - 19.6( tan^{2} o + 1)  Equation 4

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In order to get a quadratic equation that can be easily solve.

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                    Q_{1} = 101.6291

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                 tan ∅ = 101.63    or tan ∅ = 0.4114

Taking the Tan inverse of each value of Q

                  ∅ = 89.44°     ∅ = 22.37°

             

4 0
3 years ago
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Answer:

The time it will take for the driver to reach Ottawa is 3 hours 32 minutes and 45 seconds

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The time it takes from Toronto to Ottawa while driving at 425.5 km/h = 12765 seconds.

4 0
3 years ago
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