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lisabon 2012 [21]
3 years ago
14

Derive an equation of motion s=ut+1/2at2 for an object moving in straight line​

Physics
1 answer:
igor_vitrenko [27]3 years ago
5 0

Answer:

sut12at2

Explanation:

sorry just need points

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Engineering solutions use scientific laws to predict behaviors of objects in certain situations. Will used Newton's Laws of Moti
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D) Scientific laws do not account for unseen variations, like wind

Explanation:

Will model in predicting the path of an arrow he was about to shoot failed because scientific laws most times do not account for unseen variations like wind.

Scientific laws are the description of an observed phenomenon in nature.

  • Most scientific laws have exceptions.
  • Exceptions in scientific laws are conditions in which the law will not hold true.
  • There are exceptions to newton's law of motion which Will did not take into account.

learn more:

Newton's law brainly.com/question/11411375

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The Sl unit for speed is
34kurt

Answer:

m/s (meters per speed)

Explanation:

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A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?
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100N describes the weight of the sandbag, while 100kg is the mass of the sandbag.

To calculate acceleration, divide your weight by the mass, thus the accleration is:

100N/100kg = 1(m/s^2)
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3 years ago
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A gas is collected from a radioactive material; upon inspection, the gas is identified as helium. the presence of the helium ind
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The presence of helium gas indicates the radioactive sample is most likely decaying by α-decay, or alpha decay. α-decay is the type of radioactive decay in which an atomic nucleus emits α particles. α particles are Helium nuclei. So the correct answer would be α-decay.
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Suppose someone pours 0.250 kg of 20.0ºC water (about a cup) into a 0.500-kg aluminum pan with a temperature of 150ºC. Assume th
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Answer : The temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of aluminium = 0.90J/g^oC

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of aluminum = 0.500 kg = 500 g

m_2 = mass of water = 0.250 kg  = 250 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of aluminum = 150^oC

T_2 = initial temperature of water = 20^oC

Now put all the given values in the above formula, we get:

500g\times 0.90J/g^oC\times (T_f-150)^oC=-250g\times 4.184J/g^oC\times (T_f-20)^oC

T_f=59.10^oC

Therefore, the temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

8 0
4 years ago
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