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Doss [256]
3 years ago
8

Find the 20th term from the last term of the AP:3,8,13,..., 253. ​

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0

Answer:

158

Step-by-step explanation:

The sequence is 3, 8, 13, ..., 253.

Going backwards, it's 253, 248, 243, ..., 3.

First term is 253, common difference is -5.

The nth term is:

a = 253 − 5(n − 1)

The 20th term is:

a = 253 − 5(20 − 1)

a = 158

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Answer:

PLease

Step-by-step explanation:

4 0
3 years ago
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15 + brainliest help me please
Fiesta28 [93]
2f +4f +2 -3
 combine the like terms to get 6f-1

 so yes they are equivalent

2f+4f+2-3 at f=3 would also be 17


8 0
3 years ago
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Barney's Book Store currently has 2000 books in stock. There are 3 times as many non-fiction books as fiction books. Determine t
xxMikexx [17]

Answer:

There are 1500 non fiction books and 500 fiction books currently in the store.

Step-by-step explanation:

Given:

Total Number of books = 2000

Let the number of fiction books be 'x'.

Now given:

There are 3 times as many non-fiction books as fiction books.

Number of non fiction books = 3x

We need to find the number of non-fiction and fiction books.

Solution:

Now we know that;

Total Number of books is equal to sum of the number of non-fiction and fiction books.

framing in equation form we get;

x+3x=2000\\\\4x=2000

Dividing both side by 4 we get;

\frac{4x}{4}=\frac{2000}{4}\\\\x= 500\ books

Number of fiction books = 500

Number of non fiction books = 3x=3\times 500 =1500

Hence There are 1500 non fiction books and 500 fiction books currently in the store.

8 0
3 years ago
23 over.30 ÷20 over 24
alexgriva [62]

Remark

Don't try and do this all at once. Break it down, otherwise you'll have layers and brackets all over the place.

Step One

Find 23/0.3

X = 23/0.3 = 76.7

Step Two

Now Divide by 20

x1 = 76.7 / 20

x1 = 3.83

Step Three

Take this result and put it over 24

x2 = x1/24

x2 = 3.83 / 24

x2 = 0.1597 <<<< Answer

6 0
3 years ago
Read 2 more answers
Please help with this
ioda

Answer:

Some have multiple choices. See below for additional comments.

  • a) iii
  • b) i
  • c) v
  • d) ii
  • e) iv

Step-by-step explanation:

i -- slope-intercept form. Shows the slope and the y-intercept

ii -- slope-intercept form. Shows the slope and the x-intercept

iii -- intercept form. Shows both the x- and y-intercepts

iv -- standard form.

v -- point-slope form. Shows the slope and one point on the line.

vi -- another point-slope form. Shows the slope and one point on the line

__

With the above forms in mind, ...

a) both intercepts are best shown in form iii

b) the slope is shown in forms i, ii, v, vi. Form i is the most uncluttered.

c) points are shown in forms v and vi. Form v may be least confusing.

d) the sign can be readily determined in form ii.

e) testing the given point is easily done using forms ii and iv. Form iv may be the best for this.

_____

<em>Additional comments</em>

Since each of these forms of the equation has utility in different situations, it can be worthwhile to learn the different forms. For example, I like the standard form for making perpendicular lines, though any of the "slope-" forms can be useful for that, too. The useful form to start with will be the one that best relates to the information given. (For two points given, there is a "2-point form" not shown here.)

6 0
3 years ago
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