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3 years ago

What two-dimensional cross section do a cube and a square pyramid have in common?

Mathematics

1 answer:

TEA [102]3 years ago

4 0

Answer:

D. Square

Step-by-step explanation:

Neither a Cube or a Square pyramid have an ellipse, hexagon or octagon on them anywhere, and a cube doesn't have a triangle on it, so the only thing out of these choices that these even have in common is a square.

I hope this explains it!

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How to solve it using elimination

gregori [183]

X=3
y=5

You have to cancel out either the x values or the y values (I chose y). You multiply both equations by particular numbers so either the x values or y values can be equal to each other, as well as positive or negative to each other. I multiplied -7y by 4 and 4y by 7, and got -28y and 28y. I then canceled those out. The numbers you multiply by also affects the rest of the equations, so I ended up with 48x=4 and -35x=35. After that, you combine like terms, which results in 13x=39. You divide 13 by both sides and you end up with x=3. To find y, all you have to do is plug in the x value to one of the equations, then solve for y. I resulted in y=5.

Hope this helped ^_^

8 0

2 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

2 years ago

Write each number in standard form 6.7x10 to the 1 power

e-lub [12.9K]

<h2>Answer: 67</h2>

Step-by-step explanation: 6.7 x 10^1 = 67

8 0

2 years ago

Fritz is recording the decay of radioactive material. The table displays the

damaskus [11]

Answer:

Every week, the radioactivity decreases by a factor of 5

After 1 week, it goes from 5,000 to 1,000

2 weeks 1,000 / 5 =200

3 weeks 200 / 5 = 40

4 weeks 40 / 5 = 8

5 weeks 8 / 5 = 1.6

6 weeks 1.6 / 5 = 0.064

7 weeks 0.064 / 5 = 0.0128

8 weeks .0128 / 5 = 0.00256

9 weeks 0.00256 / 5 = 0.000512

10 weeks 0.000512 / 5 = 0.0001024

Step-by-step explanation:

3 0

2 years ago

Anybody who is good with word problems and (who has done these before) plz help thx!!! :DD

vovikov84 [41]

1. $\frac{x}{15} = 3$

2. 8x = 216

6 0

2 years ago

Read 2 more answers