Answer:
8^2+x + 2^ 3x = 32^ 1/2
2^3(2+x) + 2^3x = 2^5^1/2
All two's will cancel out
3(2+x) + 3x = 5^1/2
6+3x + 3x = 5^1/2
6 +6x = 2.23
6x = 2.23 - 6
6x = -3.77
x = -3.77÷ 6
x = -0.63
Given:
A number when divided by 780 gives remainder 38.
To find:
The reminder that would be obtained by dividing same number by 26.
Solution:
According to Euclis' division algorithm,
...(i)
Where, q is quotient and
is the remainder.
It is given that a number when divided by 780 gives remainder 38.
Substituting
in (i), we get

So, given number is in the form of
, where q is an integer.
On dividing
by 26, we get




Since q is an integer, therefore (30q+1) is also an integer but
is not an integer. Here 26 is divisor and 12 is remainder.
Therefore, the required remainder is 12.
19 is a prime number so 1, 19
hope this helps!
777 divided by 21 = 34 with a remainder of 3