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asambeis [7]
4 years ago
13

One year after graduating from college, Sam earned $42,000. Each year, he earned $4000 more.

Mathematics
2 answers:
Temka [501]4 years ago
8 0

Answer:

=4000n+38,000

Step-by-step explanation:


xxMikexx [17]4 years ago
4 0
The answer is:
an=4000n+38,000

Sam has $42,000 one year after graduating. So when he graduates, he would have $38000.

Hope this helps!

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At Garland School, 3/5 of the 490 students are boys.
Masja [62]

Step-by-step explanation:

the bowood school by 455 kids

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3 years ago
Of the coins in simones’s collection there is 13/25 are quarters. Of those quarters 2/3 are are state quarters, way fraction os
Reil [10]

Answer:

13/25 * 2/3 = 26/75

 

Multiplying numerators: 13 * 2 = 26

Multiplying denominators: 25 * 3 = 75

4 0
3 years ago
The average score on a standardized test is 750 points with a standard deviation of 50 points. If 2,000 students take the test a
tatuchka [14]
I the average score is 750 and standard deviation ( sigma ) is 50 points, then score 700 - 800 is between (750 - 1 sigma) and (750 + 1 sigma).
That is 34.1 % + 34.1 % = 68.2 % of the whole population. 
2,000 · 0.682 = 1.364 
We expect 1,364 students to score between 700 and 800 points. 
6 0
4 years ago
I really need help with this question please someone help me
Radda [10]

\mathrm{Inverse\:of}\:\frac{7}{x}-9:\quad \frac{7}{x+9}

\mathrm{Inverse\:of}\:\frac{x}{6}+8:\quad 6x-48

\mathrm{Inverse\:of}\:5x-11:\quad \frac{x+11}{5}

\mathrm{Inverse\:of}\:2+\sqrt[3]{x}:\quad x^3-6x^2+12x-8

4 0
3 years ago
A weight suspended by a spring vibrates vertically according to the function D D given by D(t)=2sin(4π(t+18)) D ( t ) = 2 sin (
STALIN [3.7K]

Answer:

21.75 cm/s

Step-by-step explanation:

1 cm above central position means D = 1, so we plug in 1 into D(t) and find the time and which this occurs.

D(t)=2Sin (4\pi(t+18))\\1=2Sin (4\pi(t+18))\\\frac{1}{2}=Sin(4\pi t +72\pi)\\4\pi t + 72 \pi = \frac{\pi}{6}\\4\pi t = \frac{\pi}{6}-72\pi\\t=\frac{\frac{\pi}{6}-72\pi}{4\pi}

This is the time at which this occurs.

To find instantaneous rate of change, we differentiate D(t) and plug in this t we found. Remembering that d/dt (Sin t) = Cos t

D(t)=2Sin (4\pi(t+18))\\D(t)=2Sin(4\pi t + 72\pi)\\D'(t)=2Cos(4\pi t + 72\pi)(4\pi)

Now putting t:

D'(t)=2Cos(4\pi t + 72\pi)(4\pi)\\D'(\frac{\frac{\pi}{6}-72\pi}{4\pi})=2Cos(4\pi (\frac{\frac{\pi}{6}-72\pi}{4\pi}) + 72\pi)(4\pi)\\=8\pi Cos(\frac{\pi}{6})\\=21.75

Thus, the instantaneous rate would be around 21.75 cm/s

8 0
3 years ago
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