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choli [55]
3 years ago
6

The average score on a standardized test is 750 points with a standard deviation of 50 points. If 2,000 students take the test a

t a local school, how many students do you expect to score between 700 and 800 points?
Mathematics
1 answer:
tatuchka [14]3 years ago
6 0
I the average score is 750 and standard deviation ( sigma ) is 50 points, then score 700 - 800 is between (750 - 1 sigma) and (750 + 1 sigma).
That is 34.1 % + 34.1 % = 68.2 % of the whole population. 
2,000 · 0.682 = 1.364 
We expect 1,364 students to score between 700 and 800 points. 
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what number could be included in the data set 9,12,17,15,13 so the MEDIAN of the numbers in the set results in 14?
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<em><u>Your answer is 12,17,15,13 if you take out the 9 your median will be 14.</u></em>


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B +2.01 =5.5 what dose b equal
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Answer:

3.49

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have a great day!

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Please help!
777dan777 [17]

Answer:

\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}

Step-by-step explanation:

Use formulas for the volumes:

V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.

1. When r=1,

V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.

2. When r=2,

V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.

3. When r=3,

V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.

4. When r=4,

V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.

5. When r=5,

V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.

Note that for all r,

\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.

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