ABCD is a quadrilateral. P is a point. P is closer to C than to D. P is also closer tothe line AB than the line AD. Find and sha
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(-3,5). (2,-3)
x1,y1. x2,y2
y2-y1. -3-5. -8
--------- = ------- = ----- =8 =m
x2-x1. 2-3. -1
plug the rest in
x1,y1. x2,y2
y2-y1. -3-5. -8
--------- = ------- = ----- =8 =m
x2-x1. 2-3. -1
plug the rest in