A 1.5 standard deviation above the mean is
np + 1.5 <span>√(np(1-p))
We are given with
np = 200
p = 200/n
The standard deviation is
</span><span>√200(1-200/n))
Substituting
200 + 1.5 </span>√200(1-200/n))
By inspection, if the value of n is 200, then the radical will result to the value of 1. Only by increasing the value of n greater than 200 will the radical result to a value of less than 1 and decreasing the spread of the mean.
The answer is
the minimum is 201
the maximum is infinity
270+3s>=540. i did the math and I'm pretty sure this is the correct answer
X^13
Because you add the exponents when multiplying
