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Black_prince [1.1K]
3 years ago
10

What is the base of a triangle with a height of 14 cm and an area of 42 square cm?

Mathematics
2 answers:
sasho [114]3 years ago
5 0

Answer:

6cm

Step-by-step explanation:

area =  \frac{1}{2} \times  base \times  height \\ 42 =  \frac{1}{2}  \times b \times 14 \\ 42 =  \frac{14b}{2}  \\ 42 = 7b \\  \frac{42}{7}  =  \frac{7b}{7}  \\ base = 6cm

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

Naily [24]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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The height of the <em>water</em> depth is h = 14 + 6 · sin (π · t/6 + π/2), where t is in hours, and the height of the Ferris wheel is h = 21 + 19 · sin (π · t/20 - π/2), where t is in seconds. Please see the image to see the figures.

<h3>How to derive equations for periodical changes in time</h3>

According to the two cases described in the statement, we have clear example of <em>sinusoidal</em> model for the height as a function of time. In this case, we can make use of the following equation:

h = a + A · sin (2π · t/T + B)     (1)

Where:

  • a - Initial position, in meters.
  • A - Amplitude, in meters.
  • t - Time, in hours or seconds.
  • T - Period, in hours or seconds.
  • B - Phase, in radians.

Now we proceed to derive the equations for each case:

Water depth (u = 20 m, l = 8 m, a = 14 m, T = 12 h):

A = (20 m - 8 m)/2

A = 6 m

a = 14 m

Phase

20 = 14 + 6 · sin B

6 = 6 · sin B

sin B = 1

B = π/2

h = 14 + 6 · sin (π · t/6 + π/2), where t is in hours.

Ferris wheel (u = 40 m, l = 2 m, a = 21 m, T = 40 s):

A = (40 m - 2 m)/2

A = 19 m

a = 21 m

Phase

2 = 21 + 19 · sin B

- 19 = 19 · sin B

sin B = - 1

B = - π/2

h = 21 + 19 · sin (π · t/20 - π/2), where t is in seconds.

Lastly, we proceed to graph each case in the figures attached below.

To learn more on sinusoidal models: brainly.com/question/12060967

#SPJ1

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