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4 years ago

What is the domain of the given function?

Mathematics

2 answers:

gizmo_the_mogwai [7]4 years ago

8 0

we know that

Domain refers to the values of x for which the function exists

For the given function

the domain is $[x | x = -6,-1, 0, 3]$

and

the range is $[y | y =-7,-2, 1, 9]$

therefore

<u>the answer is the option</u>

$[x | x = -6,-1, 0, 3]$

amid [387]4 years ago

5 0

The answer is B i think. im sorry if im wrong this isnt really my specialty.

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Answer:

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Step-by-step explanation:

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3 years ago

Dorothy is using fabric to cover a photo album the width of the fabric is 5/8 of a yard the area of the fabric is 5/16 square ya

saul85 [17]

For this case we assume that the photo album is rectangular in shape and therefore the fabric too. By definition, the area of a rectangle is given by:

$A = a * b$

Where:

a: It is the length of the rectangle

b: It is the width of the rectangle

According to the problem data we have to:

$b =\frac {5}{8} \yard\\A = \frac {5} {16} \ yards ^ 2$

Substituting:

$\frac {5} {16} = a * \frac {5} {8}$

We clear "a":

$a = \frac {\frac {5} {16}} {\frac {5} {8}}\\a = \frac {5 * 8} {16 * 5}\\a = \frac {8} {16}\\a = \frac {1} {2}$

Thus, the length of the fabric is $\frac {1} {2} yards.$

ANswer:

The length of the fabric is $\frac {1} {2} yards.$

5 0

4 years ago

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

3 0

4 years ago