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Anettt [7]
3 years ago
5

Use the number line to find 1/4+-21/8

Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer:

(Decimal: -2.375) = -19/8

nikdorinn [45]3 years ago
5 0

Answer:

-\frac{19}{8}

Step-by-step explanation:

\frac{1}{4}-\frac{21}{8}=\frac{2}{8}-\frac{21}{8}=\frac{2-21}{8}=-\frac{19}{8}

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3/4 of a right angle, 5/4 of a right angle, 5/3 of a right angle, and 2/3 of a full turn
aniked [119]
1.3/4 of right angle is 3/4*90=67.5
2.5/4 of right angle is 5/4*90=112.5
3.5/3 of right angle is 5/3*90=150
4.2/3 of right angle is 2/3*90=60
4 0
3 years ago
Please help me do this question
bija089 [108]

Answer:

I would say three person(s).

4 0
3 years ago
Read 2 more answers
The ratio of boys to girls in a school is 5:8.If the number of girls exceeds the number of boys by 144, calculate the total numb
True [87]

Answer:

Step-by-step explanation:

624 students

Since they’re only 3 parts more girls then boys and the number equals 144, you just have to divide 144 by 3. You’ll get 48

Multiply 5 and 8 by 48 to get 240 and 384 and add to get 624 which is the answer

4 0
3 years ago
Write the series using summation notation.<br><br> 4 + 8 + 12 + 16 + 20+ . . . + 80
zhannawk [14.2K]

Answer:

\sum ^{20} _{n \to \11} 4n

Step-by-step explanation:

In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;

4, 8, 12, 16, 20...80

The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d

a is the first term = 4

d is the common difference = 21-8 = 8-4 = 4

n is the number of terms

On substituting, Tn = 4+(n-1)4

Tn = 4+4n-4

Tn = 4n

The nth term of the series is 4n.

Since the last term is 80, L = 4n

80 = 4n

n = 80/4

n = 20

This shows that the total number of terms in the sequence is 20

According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;

4 + 8 + 12 + 16 + 20+ . . . + 80  = \sum ^{20} _{n \to \11} 4n

4 0
3 years ago
Imagine that the average weight of a total of 500 girls in a high school is 35kg. Tom randomly sampled 10 girls and measured the
Naddik [55]

Answer:

The sample 2 has a lowest value of SE corresponding to the least sample variability.

Step-by-step explanation:

As the value of the sample means and standard deviations are not given, as similar question is found online from which the values of data is follows

The data is as attached with the solution. From this data

Sample 1 has a mean of 34 and a SE of 5

Sample 2 has a mean of 30 and a SE of 2

Sample 3 has a mean of 26 and a SE of 3

Sample 4 has a mean of 38 and a SE of 5

As per the measure of the sample variability is linked with the value of SE or standard error. Which is lowest in the case of sample 2 .

So the sample 2 has a lowest value of SE corresponding to the least sample variability.

4 0
3 years ago
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