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emmainna [20.7K]

3 years ago

13

A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 inches. Let X be the

length of a side of the base of the box

1 answer:

Brrunno [24]3 years ago

7 0

Answer:

V = (l)(w)(h)

V = (x)(x)(20-x)

V = x²(20-x)

V = -x³ + 20x²

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kvasek [131]

Answer:

4:3

Step-by-step explanation:

divide both sides by 5 giving you 4:3

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What is the simplified form of the equation 4/5n - 1/5 = 2/5n ?

Gnoma [55]

we are given

$\frac{4}{5}n -\frac{1}{5} =\frac{2}{5}n$

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now, we can simplify it

$4n-1 =2n$

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4 years ago

A parallelogram with four right angles? Which one is it??

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Which of the following equations has no solution?

daser333 [38]

Answer:

B. 3x+5−4x=−(x+8)

Explanation:

3x+5−4x=−(x+8)

Step 1: Simplify both sides of the equation.

3x+5−4x=−(x+8)

3x+5+−4x=−x+−8

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−x+5=−x−8

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Step 2: Add x to both sides.

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Step 3: Subtract 5 from both sides.

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3 years ago

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The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

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3 years ago