Answer:
If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:
And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:
If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:
And the net increase can be founded like this:
So then the net increase would be:
C. 0.36 points
Answer:
uh?
Step-by-step explanation:
Answer:
When the eqn cuts the x-axis , y=0
3x=12
x=12/3
x=4
So,at x=4 is the point at which the linear equation cuts the x-axis
Answer:
Step-by-step explanation:
The area of a circle is:
"r" being the radius and π being 3.14
14. The diameter is 12. So, to get the radius, we would need to halve it. So, the radius would be 6.
Now we plug in 6 for r and 3.14 for π which makes it
which equals 113.04
15. The diameter is 9, so to get the radius we need to halve it to get 4.5
Plug in 4.5 for r and 3.14 for π and we get
which equals 63.585
16. The diameter is 18, so to get the radius we need to halve it to get 9
Plug in 9 for r and 3.14 for π and we get
which equals 254.34
17. The diameter is 8, so to get the radius we need to halve it to get 4.
Plug in 4 for r and 3.14 for π and we get
