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Lady bird [3.3K]
4 years ago
6

What is ​ 0.83¯¯¯¯ ​ expressed as a fraction in simplest form?

Mathematics
1 answer:
KonstantinChe [14]4 years ago
3 0

Answer:

83/100

Step-by-step explanation:

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There are tons of bearings in mathematics
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D = (252.to<br>de<br>Homewor<br>2 ln eoen of the following fo<br>c. 6 Tait) and ENG N3​
Oxana [17]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
The germination rate is the rate at which plants begin to grow after the seed is planted.
chubhunter [2.5K]

Answer:

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

\hat p=\frac{7}{15}=0.467 estimated proportion of seeds germinated

p_o=0.9 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:  

Null hypothesis:p\geq 0.9  

Alternative hypothesis:p < 0.9  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0
3 years ago
Katy ran a mile in 5 minutes. How many seconds are in 5 minutes? Answer without units. *
umka2103 [35]

Answer:

300 i think

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
So if Junior has 15 and she takes away 13 more and she asked 15 more candies how much did that have​
masha68 [24]
15-13 = 2

2+15 = 17

so 17 is your answer
5 0
3 years ago
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