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MAVERICK [17]
3 years ago
7

Pls answer urgent now maths

Mathematics
2 answers:
NISA [10]3 years ago
6 0

Answer:

The answer would be 12 because you would do 44 divided by 3 2/3

Umnica [9.8K]3 years ago
4 0

Answer: 12m^{2}

Step-by-step explanation: To find the missing length, all we need to do is divide the known length by the area:

44 ÷ 3 2/3

We need to convert this mixed number to an improper fraction. Remember, multiply the whole number by the denominator, then add the numerator to your product (the denominator stays the same):

3 × 3 = 9

9 + 2 = 11

11/3

Now, we divide:

44 ÷ 11/3

Keep the first number, flip the second fraction, and change the sign:

44 × 3/11 = 12 m^2

You might be interested in
Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to
polet [3.4K]

Answer:

(a) The probability that X is at most 30 is 0.9726.

(b) The probability that X is less than 30 is 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is 0.7406.

Step-by-step explanation:

We are given that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked. A random sample of 200 shafts is taken.

Let X = <u><em>the number among these that are nonconforming and can be reworked</em></u>

The above situation can be represented through binomial distribution such that X ~ Binom(n = 200, p = 0.11).

Here the probability of success is 11% that this much % of all steel shafts produced by a certain process are nonconforming but can be reworked.

Now, here to calculate the probability we will use normal approximation because the sample size if very large(i.e. greater than 30).

So, the new mean of X, \mu = n \times p = 200 \times 0.11 = 22

and the new standard deviation of X, \sigma = \sqrt{n \times p \times (1-p)}

                                                                  = \sqrt{200 \times 0.11 \times (1-0.11)}

                                                                  = 4.42

So, X ~ Normal(\mu =22, \sigma^{2} = 4.42^{2})

(a) The probability that X is at most 30 is given by = P(X < 30.5)  {using continuity correction}

        P(X < 30.5) = P( \frac{X-\mu}{\sigma} < \frac{30.5-22}{4.42} ) = P(Z < 1.92) = <u>0.9726</u>

The above probability is calculated by looking at the value of x = 1.92 in the z table which has an area of 0.9726.

(b) The probability that X is less than 30 is given by = P(X \leq 29.5)    {using continuity correction}

        P(X \leq 29.5) = P( \frac{X-\mu}{\sigma} \leq \frac{29.5-22}{4.42} ) = P(Z \leq 1.70) = <u>0.9554</u>

The above probability is calculated by looking at the value of x = 1.70 in the z table which has an area of 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is given by = P(15 \leq X \leq 25) = P(X < 25.5) - P(X \leq 14.5)   {using continuity correction}

       P(X < 25.5) = P( \frac{X-\mu}{\sigma} < \frac{25.5-22}{4.42} ) = P(Z < 0.79) = 0.7852

       P(X \leq 14.5) = P( \frac{X-\mu}{\sigma} \leq \frac{14.5-22}{4.42} ) = P(Z \leq -1.70) = 1 - P(Z < 1.70)

                                                          = 1 - 0.9554 = 0.0446

The above probability is calculated by looking at the value of x = 0.79 and x = 1.70 in the z table which has an area of 0.7852 and 0.9554.

Therefore, P(15 \leq X \leq 25) = 0.7852 - 0.0446 = 0.7406.

5 0
3 years ago
What was the median number of posts made?
mariarad [96]

Using it's concept, it is found that the median number of posts made was of 8.5.

<h3>What is the median of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

In this problem, the total number of observations is the sum of the frequencies, hence:

T = 1 + 0 + 3 + 1 + 2 + 1 + 1 + 2 + 3 + 5 + 9 = 28

Even number, hence the median is the <u>mean between the 14th and the 15th elements</u>, of the ordered set, hence:

M = (8 + 9)/2 = 8.5.

To remind, the ordered set is: {0, 1, 1, 1, ..., 8, 8, 8,  9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10}

The median number of posts made was of 8.5.

You can learn more about the median at brainly.com/question/16103295

6 0
2 years ago
(2x^3-5x^2+8)(x+3)=?
Alla [95]
(2x³ - 5x² + 8)(x + 3) = ?
First step is to distribute.

2x^4 + 6x³ - 5x³ - 15x² + 8x + 24
Now combine like terms.

2x^4 + x³ - 15x² + 8x + 24

This is your answer, since you can't simplify any further or solve it without some more information.
8 0
4 years ago
Please explain I really need help
velikii [3]

Answer:

1. 1343 years

2. 9 hours

3. 39 years

Step-by-step explanation:

1. Given, half-life of carbon = 5730 years.

∴ λ = 0.693/half-life of carbon = 0.693/5730 = 0.000121

If N₀ = 100 then N = 85

Formula:- N = N₀*e^(-λt)

∴ 85 = 100 * e^(-0.000121t)

∴㏑(-0.85)=-0.000121t

∴ t = 1343 years

2. Given half-life of aspirin = 12 hours

λ = 0.693/12 = 0.5775

Also N₀ = 100 then 70 will disintegrate and N = 30 will remain disintegrated.

∴ 70 = 100 *e^(-0.05775t)

0.70 = e^(-0.05775t)

㏑(0.70) = -0.05775t

∴ t = 9 hours

3.  The population of the birds as as A=A₀*e^(kt)

Given that the population of birds fell from 1400 from 1000, We are asked how much time it will take for the population to drop below 100, let that be x years.

The population is 1400 when f = 0, And it is 1000 when f = 5

We can write the following equation :

1400 = 1000e^(5t).

∴1400/1000 = e^(5k)

∴ k = ㏑(1.4)/5

We need to find x such that 1400/100 = e^(xk)

14 = e^(xk)

∴ x = 39 years

5 0
3 years ago
The roots of Billy's plant grew to 3 inches beneath the Earth’s surface. Graph all the possible depths the roots can continue to
babymother [125]

Answer:

Step-by-step explanation:relax and claculate in ur mine

7 0
3 years ago
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